7. in triangle abc, side ab is 2 cm shorter than side
ac, while side bc is 1 cm longer than ac. if the
perimeter is 62 cm, find the lengths of the 3 sides.

AC = 21, AB = 19, and BC = 22

Step-by-step explanation:

If x is the length of AC, then:

AB = x − 2

BC = x + 1

The perimeter is the sum of all three sides:

62 = x + x − 2 + x + 1

62 = 3x − 1

63 = 3x

x = 21

Therefore:

AC = 21, AB = 19, and BC = 22

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."