Mathematics, 07.10.2019 18:30, bvghchg8812
Let upper a equals left bracket start 2 by 2 matrix 1st row 1st column negative 2 2nd column 4 2nd row 1st column 1 2nd column 3 endmatrix right bracketa=−2 41 3, and upper b equals left bracket start 2 by 2 matrix 1st row 1st column negative 2 2nd column 1 2nd row 1st column 3 2nd column 7 endmatrix right bracketb=−2 13 7.a. findabab, if possible. b. findbaba, if possible. c. are the answers in parts a and b the same? d. in general, for matrices a and b such that ab and ba both exist, does ab always equal ba? a. findabab, if possible. select the correct choice below and, ifnecessary, fill in the answer boxes to complete your choice.
Answers: 3
![A=\left[\begin{array}{cc}-2&4\\1&3\end{array}\right]](/tpl/images/0297/6720/9a40d.png)
![B=\left[\begin{array}{cc}-2&1\\3&7\end{array}\right]](/tpl/images/0297/6720/a2681.png)
![AB=\left[\begin{array}{cc}-2&4\\1&3\end{array}\right]\cdot \left[\begin{array}{cc}-2&1\\3&7\end{array}\right]=\left[\begin{array}{cc}-2\cdot (-2)+4\cdot 3&-2\cdot 1+4\cdot 7\\1\cdot (-2)+3\cdot 3&1\cdot 1+3\cdot 7\end{array}\right]=\left[\begin{array}{cc}16&26\\7&22\end{array}\right]](/tpl/images/0297/6720/3f9dc.png)
![BA=\left[\begin{array}{cc}-2&1\\3&7\end{array}\right]\cdot \left[\begin{array}{cc}-2&4\\1&3\end{array}\right]=\left[\begin{array}{cc}-2\cdot (-2)+1\cdot 1&-2\cdot 4+1\cdot 3\\3\cdot (-2)+7\cdot 1&3\cdot 4+7\cdot 3\end{array}\right]=\left[\begin{array}{cc}5&-5\\1&33\end{array}\right]](/tpl/images/0297/6720/db002.png)
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Let upper a equals left bracket start 2 by 2 matrix 1st row 1st column negative 2 2nd column 4 2nd r...
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