Asmall business ships specialty homemade candies to anywhere in the world. past records indicate that the weight of orders is normally distributed. suppose a random sample of 16 orders is selected and each is weighed. the sample mean was found to be 110 grams with a standard deviation of 14 grams. a. describe the sampling distribution for the sample mean. b. what is the standard error? c. for 90% confidence, what is the margin of error? d. based on the sample results, create the 90% confidence interval and interpret.

Answer with Step-by-step explanation:

Since we have given

n = 16

a) Describe the sampling distribution for the sample mean.

The sampling distribution of the mean is the population's mean from where the items are sampled.

It would be

b. What is the standard error?

c. For 90% confidence, what is the margin of error?

Degrees of freedom = v - 1= 16-1 = 15

Using t-table, 1.753 cuts 5% level of significance in each tail.

so, Margin of error would be

d. Based on the sample results, create the 90% confidence interval and interpret.

So, 90% confidence interval would be

(103.86,116.136)

hi!

i believe that john has 55 pieces of candy left.

!

black/brown

step-by-step explanation:

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