1)indique se as funçoes abaixo possuem ponto maximo ou ponto minimo

a) y= -3x2+5

b) y=x2 - 6x +5

c) y=x2

d) y=9x + x2 +7

2) as coordenadas do vertice v da parabola que representa a funçao f(x)=x2 - 2x -3 sao:

a) v=(1,-4)

b)v=(2,4)

c)v=(-1,4)

d)y=9x+x2+7

3)calcule o valor do delta de cada funçao quadratica e depois responda:

a) y= x2+7x+10

b) y=x2+7x+20

c)y=x2 +6x +9

qual das funcoes quadraticas acima

a) nao admite raizes reais?

b) admite 2 raizes reais e iguais?

c) possui 2 raizes reais e destintas?

7) determine os zeros da funçao y=+x2+4x-5: [tex][/tex]

step-by-step explanation:

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my answer got deleted but it's a

step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.