Find the equation of the circle: y-intercepts 4 and –8, contain (–12, –8)

  (x +6)^2 +(y +2)^2 = 72

Step-by-step explanation:

The given points are vertices of a right triangle. The circle circumscribing that triangle (through all 3 vertices) will have its center at the midpoint of the hypotenuse:

  ((0, 4) +(-12, -8))/2 = (-6, -2)

The equation of a circle with center (h, k) through point (a, b) is ...

  (x -h)^2 +(y -k)^2 = (a -h)^2 +(b -k)^2

For center (-6, -2) and point (0, 4), the equation is ...

  (x +6)^2 +(y +2)^2 = (0+6)^2 +(4 +2)^2

  (x +6)^2 +(y +2)^2 = 72

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

5050 i think

step-by-step explanation: