The number n(t) of people in a community who are exposed to a particular advertisement is governed by the logistic equation. initially, n(0) = 600, and it is observed that n(1) = 1200. solve for n(t) if it is predicted that the limiting number of people in the community who will see the advertisement is 60,000. (round all coefficients to four decimal places.)

Step-by-step explanation:

The equation will be given by

Here N(0) ist the initial value and k is the charge capacity. Using the information of the question we have and .

We need to find the a value, using the logístic equation:

Isolating a, we have:

This way the logistic equation to this problem is:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3