Suppose there are two full bowls of cookies. bowl #1 has 10 chocolate chip and 30 plain cookies, while bowl #2 has 20 of each. our friend fred picks a bowl at random, and then picks a cookie at random. we may assume there is no reason to believe fred treats one bowl differently from another, likewise for the cookies. the cookie turns out to be a plain one. how probable is it that fred picked it out of bowl #1?

answer:

to get a plain cookie:

we could have (1,p) or (2,p)

prob (1, p)= (1//40) = 3/8

prob (2,p) = (1/2)(20/40) = 1/4

prob(plain cookie) = 3/8 + 1/4 = 5/8

(checking:

prob(1,c) = (1/2)(10/40) = 1/8

prob(2,c) = (1/2)(20/40) = 1/4

note 3/8+1/4+1/8+1/= 1 , check! )

could have stopped at

prob (1, p)= (1//40) = 3/8

step-by-step explanation:

the answer is 3/5

step-by-step explanation:

first divide 24 divided by 8 because that is the least common multiple

then divide 40 by 8

then you will get 3/5.

idk this answer sorry cant on this one.

step-by-step explanation: