One number is 10 more than twice another. their sum is 1 . find the numbers.

One number is 10 more than twice another.Their sum is 1.The numbers are -3 and 4

Solution:

Given that one number is 10 more than twice the other.

Let us consider the two numbers as “x” and “y”

First number = x

Second number = y

From question, consider “y” is 10 more than twice the “x”. This can be represented  

y = 10 + 2x – eqn 1

given that the sum of numbers is 1. Hence we get

x + y =1

substituting the value of “y” we get

x + 10 +2x = 1

3x +10 = 1

3x = -9

x = -3

substitute x = -3 in eqn 1 to get the value of “y”

y = 10 +2(-3)

y=10 – 6 = 4

hence the two numbers are -3 and 4

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

which expression represents the approximate length of bc?

step-by-step explanation: