Triangle def has vertices d(−4, 1), e(2, 3), and f(2, 1) and is dilated by a factor of 3 using the point (1, 1) as the point of dilation. the dilated triangle is named δd'e'f'. what are the coordinates of the vertices of the resulting triangle?

begging someone for : (

Step-by-step explanation:

Since the center of dilation is not at the origin, we can use the following formula in order to find the coordinates of the vertices of the triangle D'E'F':

Where "O" is the center of dilation at (a,b) and "k" is the scale factor.

In this case you can identify that:

Therefore, susbtituting values into the formula shown above, you get that the coordinates ot the resulting triangle D'E'F, are the following:

Vertex D' →

Vertex E' →

Vertex F' →

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

i would say b) is your answer

sorry if im wrong

step-by-step explanation: