•trey attended a new year's eve event and watched a ball drop at midnight. prior
to midnight, the bottom of the ball was 150 feet above the ground. if trey's
horizontal line of sight is 6 feet above the ground and he stands 80 feet from the
base of the pole the ball is on, what is the angle of elevation, x?

x=60.9°

Step-by-step explanation:

Given that the height of ball from the ground is 150ft

The base of the pole with the ball is 80 ft from where Trey is standing

Trey's horizontal line of sight is 6 feet above ground, then;

The height of ball from Trey's horizontal line of sight is;

150ft-6ft = 144ft

To find the angle x, assume a triangle with a base of 80 ft , a height of 144 ft and a slant height that represent the line of sight at an angle x

To get angle x , you apply the tangent of an angle formula where;

tan Ф°= length of opposite site of the angle/length of the adjacent side of the angle

tan x°= 144/80

tan x°=  1.8

x°= tan⁻(1.8)

x°=60.9°

idk this answer sorry cant on this one.

step-by-step explanation:

mxb67

step-by-step explanation: