to the nearest tenth, what is the area of the shaded segment when bn = 8 ft?

a)22.6 ft2

b)53.2 ft2

c)39.3 ft2

d)72.8 ft2

The area of the shaded segment is approximately

Solution:

Note: Refer the image attached below.

As given, BN = 8 ft

So radius r = 8

The angle c =

We know that the area of the shaded part is

(// putting the value of r and c

)

(// putting value of   sin⁡(120))

 (//putting value of π and √3 )

= 39.2288 which is approximately, 39.3

So, the area of the shaded part is

y=mx+b

step-by-step explanation:

m slope

b y-intercept