Let a, b, and c be sets where anbnc =0. is it true that |au buc| = |a| + |b| + |c|? (compute examples before trying to prove this.) some

Hello!

So we have the sets A, B and C, and we also know that A∩B∩C = 0, (this means that there is not a common element to all the sets) and we want to know if it implies that A∪B∪C = IAI + IBI + ICI

Let's find a counterexample!

Let's suppose that A and B have an object in common, but this object is not in C, then we still have that A∩B∩C = 0 but not A∪B∪C = IAI + IBI + ICI.

suppose that A = {1, 2}, B = {2,3}, C={4.5}

then  A∩B∩C = (A∩B)∩C = {2}∩{4,5} = 0

And because A and B have an element in common, the second part is not true.

step-by-step explanation:

when the line is solid:

when the line is dashed:

this > inequality sign means:

this < inequality sign means:

this > inequality sign means:

this < inequality sign means:

about the problem:

srry i'm not done ! i'll