The florist ordered tulips in bunches of 4, daisies in bunches of 10 and carnations i. bunches of 8.

if she ordered the same number of each number of each kind of flower, what is the smallest number of each tulips, daisies, and carnations she could have ordered

tulips: 10 bunches, daisies: 4 bunches, and carnations: 5 bunches

totaling 40 of each type of flower

Step-by-step explanation:

This problem involves finding the Least Common Multiple (LCM) of the three numbers: 4, 10, and 8 (which are the number of flowers that come in each bunch type).

Therefore we proceed to write each of them in prime factor form to investigate what factors we need to include for the LCM we want to find.

Therefore, we need to include for the LCM the following factors:

We need a total of 40 of each flower type which means;

For the tulips (which come in bunches of 4): bunches.

For the daisies (which come in bunches of 10): bunches.

For the carnations (which come in bunches of 8): bunches.

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .