Aspeedy rabbit is hopping to the right with a velocity of 4.0m/s when it sees a carrot in the distance. the rabbit speeds up to its maximum velocity of 13m/s with a constant acceleration 2.0m/s2 rightward.

how many seconds does it take the rabbit to speed up from 4.0m/s to 13m/s

t = 4.5 seconds

Step-by-step explanation:

initial velocity = 4.0 m/s

final velocity = 13 m/s

acceleration = 2.0 m/s2

t = (final velocity - initial velocity) / acceleration

t = (13 - 4.0) / 2.0

t = 4.5 seconds

Step-by-step explanation:

We know that:

Now, to calculate the time, we must use this equation:

This means that the rabbit needs 4.5 seconds to speed up from 4m/s to 13 m/s. In this type of problem, we just need to read carefully if there are initial () and final speed (), and acceleration, because that's the case when we use the equation showed.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

reduce the friction between its moving parts

step-by-step explanation:

in fact, by reducing the friction between the moving parts of the machine, it is possible to reduce the energy wasted due to this friction; therefore, more input energy is converted into useful work, and this will improve the efficiency of the machine.