3. let h(t) = 16t – 4t -1. evaluate h(3).

h(3) = 35

Step-by-step explanation:

Simplify h(t) = 16t - 4t - 1   to h(t) = 12t -1

Then, plug 3 into the t

h(3) = 12*3 - 1 = 36 - 1 = 35

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

is this part of a question or something