Alumco manufactures aluminum sheets and aluminum bars. the maximum production capacity is estimated at either 800 sheets or 600 bars per day. the maximum daily demand is 550 sheets and 560 bars. the profit per ton is $40 per sheet and $35 per bar. determine the optimal daily production mix

The optimal daily production is 550 sheets and 387.5 bars.

Step-by-step explanation:

Let x be the no. of sheets

Let y be the no. of bars

The profit per ton is $40 per sheet and $35 per bar.

So, Profit function = 40x+35y

The maximum daily demand is 550 sheets and 560 bars.

So,

Now we are given that The maximum production capacity is estimated at either 800 sheets or 600 bars per day

So, equations becomes :

Plot the equations on the graph

So, The points of feasible region are : (53.333,560),(320,560),(550,387.5) and (550,187.5)

Profit function = 40x+35y

At(53.333,560)

Profit  = 40(53.333)+35(560)=21733.32

At (320,560)

Profit  = 40(320)+35(560)=32400

At (550,387.5)

Profit  = 40(550)+35(387.5)=35562.5

At (550,187.5)

Profit  = 40(550)+35(187.5)=28562.5

Since profit is maximum at (550,387.5)

So,  the optimal daily production is 550 sheets and 387.5 bars.

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