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Mathematics, 02.10.2019 23:00, jonataespi5924
We say a function f: a -> b is injective (one-to-one) iff for all xe a, r2a, f(x1) = f(x2) implies r = r2. what does it mean for a function not to be injective?
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We say a function f: a -> b is injective (one-to-one) iff for all xe a, r2a, f(x1) = f(x2) impl...
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