The sum of two numbers is 99, and one of them is 17 more than the other. what are the two numbers?

sum of two numbers = 99

let the smaller number be 'x' and the bigger number be x+17

x + (x + 17) = 99

x + x + 17 = 99

2x = 99 - 17

2x = 82

x = 82/2 = 41

therefore, the two numbers are 41 and 41 + 17 = 58

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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4400

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