Students in the school band are selling calendars. they earn $0.40 on each calendar they sell.
their goal is to earn more than $327. write and solve an inequality to find the fewest number of
calendars they can sell and still reach their goal.

The fewest number of calendars they can sell is 813

Step-by-step explanation:

Hi, to answer this question we have to write an inequality with the information given:

The number of calendars that they sell is represented with the variable x, we have to multiply that variable for the amount that they earn per calendar (0.40).

That expression must be equal or higher than their goal (325)

0.40x ≥325

Solving for x:

x ≥325/40

x≥812.5

x≥813 (rounded, since if they sell 812 they don't reach their goal)

The fewest number of calendars they can sell is 813.