51,29 749 737 7. you have 5 distance packages labeled 1,2,3,4,5. you have to mail them on 2 consecutive days with at least one package mailed each day. in how many different ways can this be done? explain.

There are 75 ways.

Step-by-step explanation:

Given : You have 5 different packages labeled 1,2,3,4,5. You have to mail them on 2 consecutive days with at least one package mailed each day.

To find : In how many different ways can this be done?

Solution :

5 different packages labeled 1,2,3,4,5.

You have to mail them on 2 consecutive days with at least one package mailed each day.

The possible number of ways are

1) ways

2) ways

3) ways

4) ways

Total number of ways can this be done is 20+30+20+5=75.

Therefore, There are 75 ways.

a) 0,0; 1,1; and 2,2

step-by-step explanation:

these have the exact same coordinates, thus they are the correct function.

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)