Mathematics, 02.10.2019 06:10, bks53

Between 10 p. m. and
7: 45 a. m., the water level in a swimming pool
decreased by 13/16 inch.
assuming that the water level decreased at a
constant rate, how much did it drop each hour?

Answers: 1

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Answers

answered: dan7478

The water level dropped $\frac{1}{12}$ inch each hour

Step-by-step explanation:

- Between 10 P.M. and 7:45 A.M., the water level in a swimming pool

decreased by 13/16 inch

- Assuming that the water level decreased at a constant rate

- We need to find the drop each hour that means the unit rate of

decreased of the level of the water

- At first lets hind how many hours between 10 P.M. and 7:45 A.M.

∵ Between 10 P.M. and mid-night 2 hours

∵ Between mid-night and 7:45 A.M. 7 hours and 45 minutes

- Lets change 7 hours and 45 minutes to hours

∵ 1 hour = 60 minutes

∴ 45 minutes = 45 ÷ 60 = $\frac{3}{4}$ hours

∴ 7 hours and 45 minutes = $7\frac{3}{4}$ hours

∴ The total hours between 10 P.M. and 7:45 A.M. = 2 + $7\frac{3}{4}$ hours

∴ The total hours between 10 P.M. and 7:45 A.M. = $9\frac{3}{4}$

∵ The unit rate of decreased = The decreased level ÷ total hours

∵ The decreased level is $\frac{13}{16}$ inche

∵ The total hours = $9\frac{3}{4}$ hours

- Lets change the mixed number $9\frac{3}{4}$ to improper fraction

∵ $9\frac{3}{4}$ = $\frac{(9*4)+3}{4}$

∴ $9\frac{3}{4}$ = $\frac{39}{4}$

∵ The unit rate of decreased = $\frac{13}{16}$ ÷ $\frac{39}{4}$

- To solve the division of 2 fractions change the division sign to

multiplication sign and reciprocal the fraction after the division sign

∴ The unit rate of decreases = $\frac{13}{16}$ × $\frac{4}{39}$

∴ The unit rate of decreases = $\frac{1}{12}$ inch per hour

The water level dropped $\frac{1}{12}$ inch each hour

answered: calc14

$\frac{1}{12}$ inches per hour.

Step-by-step explanation:

Between 10 P.M. and 7:45 A.M., the water level in a swimming pool decreased by $\frac{13}{16}$ inch.

First we calculate the hours between 10:00 P.M and 7:45 A.M.

10:00 P.M. = 22:00 P.M.

10:00 p.m. + 2 hours = 12:00 a.m.

so 2 hours + 7 hours and 45 minutes = 9 hours 45 minutes

9 hours 45 minutes = $9\frac{3}{4}$ = $\frac{39}{4}$ hours

It takes $\frac{39}{4}$ hours to decrease the water level by $\frac{13}{16}$ inches.

In 1 hour the water level would decrease = $\frac{\frac{13}{16}}{\frac{39}{4} }$

= $\frac{13}{16}$ × $\frac{4}{39}$

= $\frac{13}{4\times 39}$

= $\frac{13}{156}$

= $\frac{1}{12}$ inches/hour

The water level decreased at a $\frac{1}{12}$ inches each hour.

answered: Guest

25 is obviously the correct answer

answered: Guest

i dont have an answer

step-by-step explanation:

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Between 10 p. m. and
7: 45 a. m., the water level in a swimming pool
decreased by 13/16 in...