Find three consecutive integers such that the largest is 3 less than twice the smallest

The three consecutive integers are 5,6,7

Step-by-step explanation:

Let the three consecutive integers be represented as x,x+1,x+2

As per the requirement, largest integer is 3 less than twice the smallest.

=> x+ 2 = 2x -3

=> 2x -x = 2+3

=> x= 5

So the three integers are 5,6,7

Verification:

Largest integer = 7

Smallest integer = 5

2 * smallest integer - 3 = 2* 5 - 3 = 7

Largest integer is also 7.

So the required condition in the question is satisfied by these three integers.

the anwser is d) 75°

step-by-step explanation:

step-by-step explanation:

to find if any function is an inverse of the other, put the first equation in as x in the next one. then simplify and solve. if at the end you get the statement y = x, then it is an inverse. if you get anything else, it is not.