If lisa’s gross pay was $1204.89 and her net pay was $818.44, about what percent of her pay was deducted?

1.5%

32%

47%

68%

About 32% of her pay was deducted ⇒ 2nd answer

Step-by-step explanation:

Lisa’s gross pay was $1204.89

Her net pay was $818.44

We need to find the percentage of the amount deducted from her pay

Lets calculate the deduction amount

The deduction amount is the difference between the gross pay and

the net pay

∵ The amount deducted = gross pay - net pay

∵ Gross pay = $1204.89

∵ Net pay = $818.44

∴ The amount deducted = 1204.89 - 818.44 = $386.45

Now lets find the percentage of the amount deducted

∵ Percent of deducted = [amount deducted/gross pay] × 100%

∵ The amount deducted = $386.45

∵ Gross pay = 1204.89

∴ Percent of deducted = × 100%

∴ Percent of deducted = 32.07%

About 32% of her pay was deducted

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.