Explain why the initial value of any function of the form f
(x) = a(b') is equal to a.

THE ANSWER ON E2020

Step-by-step explanation: When you substitute 0 for the exponent x, the expression simplifies to a times 1, which is just a. This is because any number to the 0 power equals 1. Since the initial value is the value of the function for an input of 0, the initial value for any function of this form will always be the value of a.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

your question is incomplete, write all the numbers in the sequence that it tells you.  

step-by-step explanation: