Which is the solution set of the compound inequality 3.5x-10> -3 and 8x-9< 39

All real numbers greater than 2 and less than 6

Step-by-step explanation:

we have

----> inequality A

-------> inequality B

Solve the inequality A

Adds 10 both sides

Divide by 3.5 both sides

The solution of the inequality A is the interval ----> (2,∞)

Solve the inequality B

Adds 9 both sides

Divide by 8 both sides

The solution of the inequality B is the interval ----> (-∞,6)

The solution of the compound inequality is

(2,∞) ∩ (-∞,6) =(2,6)

All real numbers greater than 2 and less than 6

Step-by-step explanation:

The given compound inequality :   and

Consider ,

[Adding 10 both sides]

      ...(i) [Dividing both sides by 2]

Consider,

 [Add 9 both sides , we get]

 .....(ii)[Divide both sides by 8]

From (i) and (ii) , we have

Thus , the solution is   [values 2 and 6 are not included]

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer