Don't understand

what are the domain and range of the function {(5, 3), (7, 1), (11, –2), (4, 9), (–2, 4)}?

a.
domain: {3, 1, 9, 4}; range: {5, 7, 11, 4, }

b.
domain: {3, 1, –2, 9, 4}; range: {5, 7, 11, 4, –2}

c.
domain: {5, 7, 11, 4, }; range: {3, 1, 9, 4}

d.
domain: {5, 7, 11, 4, –2}; range: {3, 1, –2, 9, 4}

Domain is the inputs
range is outputs from inuting inputs

normally domain=x
range=y
(x,y)
domain is all first number
range is all second numbers

we have
(5, 3), (7, 1), (11, –2), (4, 9), (–2, 4)
remember to ignore repeats
Domain: {-2,4,5,7,11}
Range: {-2,1,3,4,9}
D

2x^2 -2x -12 = 02(x -3)(x +2) = 0see below for explanation

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.

It is blindness and randomization