Aunit dose of levalbuterol hcl contains 3.0 ml in a 0.0417% concentration. how many unit doses are needed in order to obtain 10mg of the active ingredient?

8 unit doses

Step-by-step explanation:

A 0.0417% concentration means that 100 mL of solution contains 0.0417 grams = 41.7 mg of the active ingredient.  

Cross-multiplying  

100 mL 41.7 mg

    x mL 10 mg

100/x = 41.7/10 > x = 1000/41.7 = 23.9808 = 24 mL rounding to the nearest integer.

As a  unit dose of Levalbuterol HCL contains 3.0 mL,  

we need 24/3 = 8 unit doses to obtain 10 mg of the active substance.

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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