Graph a line that contains the point (-5,-6) and has a slope of 2/3

We can start by using the formula y = mx + b

m = slope

b = y-intercept

we are already given our slope, so we can plug that in: y = 2/3 x + b

To find b, we can plug in (-5,-6) for x and y

-6 = 2/3 (-5) + b

multiply everything by 3 to get rid of the denominator

-18 = -10 + 3b

add 10 to both sides

-8 = 3b

divide

-8/3 = b

now that we have b, we now know the entire formula:

y = 2/3 x - 8/3 is a line that contains the point (-5,-6) and has a slope of 2/3

i don't even know man. edge inuity be messing with us. i had to ask a question too.