Last one pls

adding which of the following ordered pairs to the set {(1,-2), (0,4), (2,-3)} would make it not a function?

a. (-1, -2)
b. (3, 5)
c. (0, 2)
d. (-2, 1)

Hello there!

your set is  {(1,-2), (0,4), (2,-3)} where the pairs have the form (x,y)

You want to know with pair you need to add to this set in order to make it "not a function"

The priority rule for a function is the unicity; this means that each value of x has only one value of y associated; or:

if f(x) = y1 and f(x) = y2, then y1 = y2

(notice that a given value of y can be related to different values of x; for example the function f(x) = x^2 has the same y value for x and -x)

Then the problem is if we add the pair (0,2), of option C.

because we already have a pair with the value of x = 0, in the form of (0,4), and these two pairs would have a different value of y for the same value of x, then this set doesn't represent a function anymore.

Then the correct option is C

b. hoped i'm right lol

step-by-step explanation:

answer:   expression= p+p*d%

price reduction + sale price = $625

sale price: $p+$p*d%

where d% is the percentage of discount

step-by-step explanation:

original price = p

price went down by $150 price reduction $p*d%

sale price= $ 475

therefore the price before sale is: $625

and the expression that shows the price before sale is: p+p*d%