What is the equation of the line perpendicular to the line y = start fraction 4 over 9 end fractionx – 2 that passes through the point (4, 3)?
a. y = –start fraction 4 over 9 end fractionx – 2
b. y= nine-fourthsx + 6
c. y = –nine-fourthsx + 12
d. y = –nine-fourthsx – 12

write an equation of the line that passes through points (3, 7) and (5, 11).
a. y – 7 = 5(x – 3)
b. y – 7 = 2(x – 3)
c. y + 7 = 5(x – 3)
d. y + 7 = 2(x + 3)

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step-by-step explanation:

ιт ιѕ в. 1/4

ιи (fяα¢тισи/єχα¢т fσям) 1/4

ιи (∂є¢ιмαℓ fσям) .25

нσρє ι ¢συℓ∂ нєℓρ уα

the given growth  function for the length of the fish (cm) is

f(m) = 5(1.07)m = 5.35m

where 

m = months

at the end of the study, the length is 9.19 cm. the  time for conducting the study is determined as

5.35m = 9.19

m = 1.7178 months

part a.

the study was performed over a time period  of about 1.72 months. therefore  the domain for  plotting the function is 0 < = m < = 1.72.

note:

if growth  continues at this rate for up to m months, then the domain would be 0< =m< =m.

part b.

the growth function is a linear function.

when m=0, f=0.

therefore the initial growth is zero, which represents the y-intercept.

part c.

assume that the growth function is valid for 0< =m< =9.

the average rate of change of the function is the slope of the linear function, which is 5.35 cm/month.