Ascientist needs 10 liters of a 20% acid solution for an experiment but she has only a 5% solution and a 40% solution. to the nearest tenth of a liter about how many liters of the 5% and the 40% solutions should she mix to get the solution she needs?

answer:

in this question, you want to make 10 liters 20% concentration solution by mixing 5% and 40% concentration. there should be  multiple answers to this question. assuming that the total volume of 5% and 40% solution equal to 10l(no solution wasted), then you can determine the volume of solution needed. the formula should be:

if x would be the of volume  40% solution, then the volume of 5% would be:

10 l= 40% solution volume+ 5% solution volume

10 l= x + 5% solution volume

5% solution volume= 10l-x

then the volume calculation would be:

volume20%*concentration20%= volume40%*concentration40% + volume5%*concentration5%

10 liter * 20%= x liter*40% + (10- x) liter*5%

10l * 20%= x liter * 35% + 10 liter*5%

x liter *35 = 10l * 20 - 10l *5= 10l*15

x liter = 10l *15/35= 4.28 l= 4.3l

the volume of 40% solution= 4.3l

the volume of 5% solution= 10l- 4.3l= 5.7l

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

christopher is 272,195 year old

step-by-step explanation: