Ellis's backyard has a 6.256.256, point, 25 by 6.25\,\text{m}6.25m6, point, 25, space, m patio. she would like to build a 1.5\,\text{m}1.5m1, point, 5, space, m wide extension around 333 sides of the patio, as the figure shows. she will buy 0.250.250, point, 25 by 0.25\,\text{m}0.25m0, point, 25, space, m tiles that come 252525 to a package.

how many packages does ellis need to buy to build the extension?

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step-by-step explanation:

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step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

x = -5

step-by-step explanation: