What is the equation in point-slope form of a line that passes through the points (5, -3) and (-2, 9) ? a y+3= -2(x- 5)
b y-3 = 12/7(x + 5). c y-3=-2(x+5)
d y+3= 12/7(x-5)

Line through (5, -3) and (-2, 9)

The slope is (9 - -3) / (-2 - 5) = -12/7

Point slope form, point (a,b), slope m, is

y - b = m(x-a)

When we pick the point (a,b)=(5,-3) our answer is

y + 3 = -12/7 (x - 5)

That's almost D except for the sign on the slope.  The slope is definitely negative so none of the above is correct.

the answer is D

Step-by-step explanation:

hi,

i'm 75% sure the answer is 1,1 to both lines.

have a great day

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: