Arotating light is located 15 feet from a wall. the light completes one rotation every 2 seconds. find the rate at which the light projected onto the wall is moving along the wall when the light's angle is 20 degrees from perpendicular to the wall.

This is about differential calculus.

Rate = dy/dt = 41.61 ft/s

We are told that the light is located 15 ft from the wall and completes rotation every 2 seconds. Thus; we can say that the distance of the light's projection onto the given wall is expressed as;

y = 15 tan θ

where;

θ is the angle of light perpendicular to the wall.

One rotation is completed every 2 seconds and this means that;

Angular speed; ω = 2π/2 = π

ω = θ/t

Thus;

θ = wt = πt

dθ/dt = π

Then

dy/dt = 15 sec² θ (dθ/dt)

(dy/dt) = 15π sec² θ

dy/dt = 15π sec²(20°)

dy/dt = 41.61 ft/s

Read more at; link

  53.4 ft/s

Step-by-step explanation:

The distance from the point closest to the light is ...

  d = (15 ft)tan(α)

where α is the angle from perpendicular. Since the light travels through an angle of 2π radians in 2 seconds, the angle can be represented by ...

  α = πt . . . . radians

and the rate of change of α is ...

  dα/dt = π . . . . radians/second

The rate of change of distance is ...

  dd/dt = (15 ft)sec(α)²(dα/dt) = (15π)(sec(20°)²) ft/s ≈ 53.4 ft/s

inch

step-by-step explanation:

yard and mile are too big.

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: