Tracking a satellite the path of a satellite orbiting the earth causes it to pass directly over two tracking stations a and b, which are 50 mi apart. when the satellite is on one side of the two stations, the angles of elevation at a and b are mea- sured to be 87. and 84. respectively.
(a) how far is the satellite from station a?
(b) how high is the satellite above the ground?

A)the satellite is at a distance of 1018.4 miles

B) the height of the satellite above the ground is 1017 miles.

Step-by-step explanation:

The diagram below shows the situation graphically so it's easier to understand.

To calculate this we need to use the tangent definition I.E.

so for angle at point A it would be

tan(87) = h /x

for angle at pint B it would be tan

(84.2) = h / (x+50)

since h is the same for both we can pass terms and replace, then solve for x

tan(87)*x = h

tan (84.2)*(x+50) = h

∴

tan(87) * x = tan (84.2) * (x+50)

=

1.938 = 1 +

1.938 -1 =

x = = 53.3 mi

then using the tangent formula from before we can calculate h

tan(87) = h / 53.3

tan (87) / 53.3 = h

h = 1017 mi

then we can use the cos formula to calculate d

cos 87 = x / d

d =  53.3 / cos 87 = 1018.4 mi

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!

i would say b) is your answer

sorry if im wrong

step-by-step explanation: