Kyle gave 2/7 of his money to his wife and spent 3/5 of the remainder. if he had $300 left, how much money did he have at first?

Kyle gave 2/7th  of his money to his wife and spent 3/5 of the remainder. If he had $300 left, the money had by Kyle at first is $1050

Solution:

Step 1:

Consider “x” as the money which Kyle had initially.  

From question, Kyle gave 2/7th of his money to his wife. So the remaining money left with Kyle is given as,

----- eqn 1

Now the remaining money left with Kyle is 5/7th.Given that Kyle spent 3/5 of the remaining money.  

Now the remaining money left with Kyle is given as  

Now kyle is left with $300, which is 2/5th of the initial money x .

We get equation as  

2x = 1500

x = 750

Now Kyle is left with 750$ which is 5/7th of the initial amount x.( by using eqn 1)

We get equation as

5x = 5250

x = 1050

So the amount had by Kyle at first is $1050

use substitution to solve each system of equations. y = x + 5 3x + y = 25 62/87,21 y = x + 5 3x + y = 25 substitute x + 5 for y in the second equation. substitute the solution for x into either equation to find y. the solution is (5, 10)

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step-by-step explanation:

answer

d. 10

explanation

the distance from point y to wx is the height of the triangle.

using pythagoras theorem,

group similar terms to get,

this implies that,

take positive square root of both sides to get,

this implies that,