Use the quadratic equation −x2+2x−2=0 to answer the questions.
a: what are the solutions to the quadratic equation?
b: which statements accurately interpret the meanings of the solutions?
select one answer for part a, and select two answers for part b.
b: since the quadratic equation has two complex solutions, the graph of the quadratic equation does not intercept the x-axis.
b: since the quadratic equation has two complex solutions, the graph of the quadratic equation intercepts the x-axis at (−1,0) and (1,0).
b: since the solutions are x=1 or x=−1, two factors of the quadratic expression −x2+2x−2 are (x+1) and (x−1).
b: since the solutions are x=i or x=−i, two factors of the quadratic expression −x2+2x−2 are (x−i) and (x+1).
b: since the solutions are x=1+i or x=1−i, two factors of the quadratic expression −x2+2x−2 are (x−(1+i)) and (x−(1−
a: x=i or x=−i
a: x=1 or x=−1
a: x=1+i or x=1−i

2,600 divided by 80 = 32.5

step-by-step explanation:

rick has $1400 and sally has $1500

step-by-step explanation:

to find amount of money rick has after 10 years :

principal = $1000 , time = 10 years , rate = 4% annually

to find amount of money sally has after 10 years :

her friend gives to pay her $50 per year, therefore money she has after 10 years = 50 × 10 = $500

also, sally gets $1000 after 10 years,

therefore, total amount of money sally has after 10 years = 500 + 1000 = $1500

so, after 10 years : rick has $1400 and sally has $1500

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

i will with my problems and all the other things that need to   be on by the way

step-by-step explanation: