Astudent of one of the authors earned grades of 63, 91, 88, 84, and 79 on her five regular statistics tests. she earned a grade of 86 on the final exam and 90 on her
class projects. her combined homework grade was 70. the five regular tests count for 60%
of the final grade, the final exam counts for 10%, the project counts for 15%, and homework
counts for 15%. what is her weighted mean grade? what letter grade did she earn (a, b, c, d,
or f)? assume that a mean of 90 or above is an a, a mean of 80 to 89 is a b, and so on.

Weighted mean grade: 81.2

Letter grade: B

Step-by-step explanation:

5 regular tests:

  (63+91+88+84+79) / 5 * 60%

= 405 / 5 * 0.6

= 48.6

Final exam:

86 * 10% = 8.6

Project:

90 * 15% = 13.5

Homework:

70 * 15% = 10.5

So her weighted mean grade is

48.6 + 8.6 + 13.5 + 10.5 = 81.2

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

yes

step-by-step explanation: