Series of questions answer them all.
1st q 5x + 5x = 10x a0
2nd q (13)^2(13)^-4(13)^5 =...
Mathematics, 25.09.2019 01:20, jaylenmiller437
Series of questions answer them all.
1st q 5x + 5x = 10x a0
2nd q (13)^2(13)^-4(13)^5 =
3rd q (4x)^-2(4x)^3(4x)^9 = (
4th q 6xy^-2 / x^-3 =
5th q (1/4x)^-2 / x^2
6th q 3x^2(9x)^0 = x
Answers: 1
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