Acircle is centered at the point (5,-4) and passes through the point (-3,2).
the equation of this circle is (x+ 1] 2+0+ 0
.
what is?

Step-by-step explanation:

We need to find the equation of the circle. First, the formula:

Where (h,k) is the center and r is the radius

The center is (5,-4), so we can say:

Now, to find the radius, we can use the distance formula to find distance between (5,4) and (-3,2).

The distance formula is  

Where

x_1 = 5

x_2 = -3

y_1 = 4

y_2 = 2

Plugging in, we get:

Hence, the radius is 10 and we can write the equation of circle as:

Step-by-step explanation:

Equation of circle having center at (h,k) :

Then, the equation of circle having center at (5,-4) and radius r will be:-

  (1)

Since, circle is passes through (-3,2).

Put x= -3 and y=-2

Putting value of in (1), we get

Hence, the equation of this circle is

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

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