12 the cost of a telephone call is $0.60 for the first three minutes plus $0.17 for each additional minute. what is the greatest number of whole minutes the telephone call can be if the cost cannot exceed $2.50?
f 8
g 11
h 14
j 18

H

Step-by-step explanation:

The total cost of the call is $2.50

Since the first three minutes cost $0.60

x minutes = $2.50 - $0.60

x minutes = $1.9

Each additional minutes cost $0.17

So: $1.9 / $0.17 = 11

To find the total minutes

$0.60 + $1.9 = $2.50

3 + 11 = total minutes

14 = total minutes

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)