Astudent takes a multiple-choice exam. suppose for each question he either knows the answer or guesses and chooses an option at random. further suppose that if he knows the answer, the probability of a correct answer is 1, but if he guesses, the probability of a correct answer is 1/4. to pass, students need to answer at least 60% of the questions correctly. the student has "studied for a minimal pass," i. e., the student knows the answer to a question with probability 0.6. given that he answers a correctly, what is the probability that he actually knows the answer? group of answer choices

The probability that he knows the answer given his answer is correct is 0.8571

Step-by-step explanation:

The problem can be solved by Bayes theorem

Let us take the Following Events

1) P(A)= probability that the student's answer is correct

2) P(B) = probability that the student knows the correct answer

For 2 events A and B Bayes theorem states that

The probability that an event 'B' occurs provided that event A has already occurred is given by "P(B|A)" as

where

P(A|B) is the probability of event A to occur provided event B has occurred

from the given data we have

P(B) = 0.6

P(A) (probability that his answer is correct = probability that his answer is correct provided he knows the answer + Probability his answer is correct provided he gambles)

Thus

Thus

answer: get jesus in your life

step-by-step explanation:

days of the week

step-by-step explanation:

javier earned more money then kyle, so that won't always be a constant term, but the days of the week do not change so that term is always constant.

edit: i meant