Someone find the answer, ill give brainliest.
find the perimeter and area of the figure shown below. use 3.14 for π. round your answer to the nearest hundredth.
perimeter =
area =

SQUARE IN THE MIDDLE

This is the easiest part: a square with side length s has area s^2, so the area of the square in the middle is

TRIANGLE ON THE LEFT

The base of this triangle is one side of the square, so it is 12 inches long. The height is given, and it is 8 inches long. The area of a triangle is half the product of width and height, and so we have

SEMICIRCLE ON THE RIGHT

The diameter of the semicircle is one side of the square, so it is 12 inches long. The radius is half the diameter, so it's 6 inches long. The area of a circle is , so the area of a semicircle will be half this quantity:

The total area is the sum of these areas:

As for the perimeter, we have:

Since the circumference of a circle is , the semicircumference will be

So, the perimeter is

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.

school a:

minimum value is 2

maximum value is 22

the lower quartile is 2.5

the median is 10

the upper quartile is 15.5

school b:

minimum value is 9

maximum value is 20

the lower quartile is 12

the median is 16

the upper quartile is 18

box plot for school a isn't symmetrical. the data tails on the right

box plot for school b isn't symmetrical. the data tails on the left

hope i

-lavira: )