given: w ∥ x and y is a transversal.
prove: ∠3 and ∠5 are supplementary.
use the drop-down menus to complete the proof.
given that w ∥ x and y is a transversal, we know that ∠1 ≅∠5 by the
a. corresponding angels theorem
b. alternate interior angels theorem
c. vertical angels theorem.
d. alternate exterior angels theorem
therefore, m∠1 = m ∠5 by the definition of congruent. we also know that, by definition, ∠3 and ∠1 are a linear pair so they are supplementary by the
a. defenition of a linear pair
b. defenition of supplementary angels
c. linear pair postulate
d. vertical angels theorem
by the m∠3 + m ∠1 = 180. now we can substitute m∠5 for m∠1 to get m∠3 + m∠5 = 180. therefore, by the definition of supplementary angles, ∠3 and ∠5 are supplementary.
a. congruent supplements theorem
b. defenition of a linear pair
c. defenition of supplementary angles
d. linear pair postulate

The coorect options are A, C and C. The corresponding angle theorem, linear pair postulate and definition of supplementary angles,

The point where two lines meet or intersect is known as an angle

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1, 3, 3

Step-by-step explanation:

A. Corresponding angles theorem

C. Linear pair postulate

C. Definition of supplementary angles

I did the assignment and got it right trust me :)

astronomers is your final answer! : )

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step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.