Assume that you have 6 dimes and 2 quarters (all distinct), and you select 4 coins. (1) in how many ways can the selection be made? equation editorequation editor (2) in how many ways can the selection be made if all the coins are dimes? equation editorequation editor (3) in how many ways can the selection be made if you select 3 dimes and 1 quarter? equation editorequation editor (4) in how many ways can the selection be made so that at least 3 coins are dimes?

Step-by-step explanation:

Given that there are 6 dimes and 2 quarters (all distinct), and you select 4 coins.

i) No of ways to select 4 coins =

ii) No of ways to select 4 dimes =

iii) No of ways to select 3 dimes and 1 qr =

iv) no of ways to select atleast 3 dimes = no of ways for 3 dimes + no of ways for 4 dimes

=

it will cost dollar $540

the living room is 3 which means if we divide 325/3 then we get $108

therefore if 1part of the living room cost $108 and 3 costed $325

then total 5part of the room will cost 5*108 which gives $540