Let x, y,z c u. if n(u) = 89, n(x) = 26, n(y) n(xn ynz)= 2, find the following values: 31, n(z) 40, n(x ny) = 8, n(x nz) = 11, n(yn z) = 10, and 1. n(x'n ynz') 2. n(x'n (yuz') 3. n(x') 63 4. n(x'uyuz')

it's

the answer is b

change of stock price/initial stock price on friday * total stock value = change of stock value

0.89/73.73 *x = 42.72

x=3539.04 = total stock value at initial stock price on friday .

total stock value at initial stock price on friday/ initial stock price on friday = number of shares

3539.04/73.73 = 48 shares

they own 48 shares of this stock