What is the value of x in the qution:
13(6x-8)=5x-6
a)98/83
b)110/73
c)-98/73
d)98/73

(D) 98/73

Step-by-step explanation:

13(6x-8) = 5x-6

First,u expand the bracket, which gives u:

13 times 6x minus 13 (times) -8. Represented figuratively as:

13(x)6x - 13(x)-8 = 5x-6

⏩ 78x - 104 = 5x-6

Then,u collect like terms

78x - 5x = -6+104. (Note: the sign changes when it passes d equal to(=) sign)

73x = 98. (Note: Since 73 is carrying d variable x,we divide both side by 73)

Therefore,the answer = 98/73

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

but which class are u may know that first