Astate administered standardized reading exam is given to eighth grade students. the scores on this exam for all students statewide have a normal distribution with a mean of 507 and a standard deviation of 39. a local junior high principal has decided to give an award to any student who scores in the top 10% of statewide scores. how high should a student score be to win this award? give your answer to the nearest integer. for on how to input a numeric answer, see the instructions for entering numeric response.

The minimum score to be obtained to place in the top 10% and win this award is, 557

Step-by-step explanation:

Since the score obtained by eighth grade students is a normal random variable with a mean and and we are interested in the minimum score required for a student to be in the top 10% of all scores, It is necessary to calculate the 90th percentile for the cumulative probability distribution of the score variable in the reading test.

The variable is a standard normal variable and therefore, is the score corresponding to the standardized value z.

We must calculate the value of k such that , then, using the inverse standard normal distribution you have to y hence

Conclusion: The minimum score to be obtained to place in the top 10% is 557

b. -7,185,024p6q5

step-by-step explanation:

find the 6th term of the expansion of (2p - 3q)11. a. -7,185,024p4q7 c. -7,185p4q7 b. -7,185,024p6q5 d. -7,185p6q5 select the best answer from the choices provided a b c d

answer: idk

step-by-step explanation: