Mathematics, 20.09.2019 00:20, elsauceomotho
The area of a photograph is 35 square inches. its length is two inches longer than its width. find the length and width of
the photograph
Answers: 1
![A=35\\Area=w^{2} +2w\\35=w^{2} +2w\\w^{2} +2w-35=0\\use\ quadratic\ formula\ to\ solve\\if\\ax^{2} +bx+c=0\\x=\frac{-b +- \sqrt[2]{b^{2}4ac } }{2a}\\ +- means\ there\ are\ 2\ solutions, we\ will\ take\ the\ positive\ one, because\ it\ is\ a\ distance.\\Now, replacing\\a=1,b=2,c=35\\\\w=\frac{-2 + \sqrt[2]{2^{2}-4*1*-35 } }{2*1}\\w=\frac{-2 + \sqrt[2]{4+140} }{2}\\w=\frac{-2+\sqrt{144} }{2} \\w=\frac{-2+12}{2}\\w=\frac{10}{2}\\w=5](/tpl/images/0244/6233/2da03.png)
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The area of a photograph is 35 square inches. its length is two inches longer than its width. find t...
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