Avan traveling at a speed of 32.0 mi/h needs a minimum of 42.0 ft to stop. if the same van is traveling 67.0 mi/h, determine its minimum stopping distance (in ft), assuming the same rate of acceleration. ft

Δx= 184.12 ft

Step-by-step explanation:

The equation you need to use is velocity as a function of displacement.

v = the speed at which the car is travelling,

and

v_o is the original speed (in this case zero).

The change in x (displacement) is how far the car travels. You will be solving for a (acceleration).

solving we get

a= 12.19

now put this acceleration value into the second case when v= 67mi/h

⇒Δx= 184.12 ft

0.85 or 85%

step-by-step explanation:

1) divide 23 by 27

2) round the decimal to the nearest 10

3) so your answer would be 0.85 or 85%

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .